How to draw lewis structure for SeBr4?
Jul 20,2026
Selenium tetrabromide (SeBr4) is primarily used as a brominating agent in specialized chemical synthesis. Here is its lewis structure and steps to draw it.

Step 1: Calculate total valence electrons
Se (Selenium, Group VIA): 6
Br (Bromine, Group VIIA): 7 × 4 = 28
Total valence electrons: 6 + 28 = 34 e?
Step 2: Determine the central atom
Se has lower electronegativity than Br; as a Period 4 element, it possesses empty d-orbitals and can accommodate an expanded octet, making it the central atom.
Skeleton: 4 Se–Br single bonds.
Step 3: Construct the σ-bond framework
4 single bonds; bonding electrons: 4 × 2 = 8 e?
Remaining electrons: 34 ? 8 = 26 e?
Step 4: Fill lone pairs on peripheral Br atoms
Each Br is connected by a single bond and requires 3 lone pairs (6 e?) to satisfy the octet rule.
Total electrons for Br lone pairs: 4 × 6 = 24 e?
Remaining electrons after allocation: 26 ? 24 = 2 e?
Step 5: Place remaining electrons on the central Se atom
2 e? = 1 lone pair located on the Se atom.
Verification of total electrons
Bonding electrons (8) + Br lone pairs (24) + Se lone pair (2) = 34 e?
Expanded octet check
Se: 4 single bonds (8 bonding electrons) + 1 lone pair (2 e?) = 10 electrons; expanded octets are permissible for Period 4 elements.
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Jul 20,2026APISELENIUM TETRABROMIDE
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